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4x^2-72x+180=0
a = 4; b = -72; c = +180;
Δ = b2-4ac
Δ = -722-4·4·180
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-48}{2*4}=\frac{24}{8} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+48}{2*4}=\frac{120}{8} =15 $
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